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limites

📚 Limites et Continuité
Cours de soutien — 2ème Bac
Prof : SOUNI MOHAMED
📍 KHENIFRA
📱 Tel / WhatsApp : 06.76.43.35.51
▶️ Chaîne YouTube : SOUNIMATH
Exercice 1 ⭐ ⭐ avec solution
Calculer les limites :
\( \displaystyle \lim_{x\rightarrow+\infty}(-3x^4+15) \qquad \lim_{x\rightarrow-\infty} \left(-\frac{x^4}{5}+14\right) \)
\( \displaystyle \lim_{x\rightarrow+\infty} (-4x^3+5x+17) \qquad \lim_{x\rightarrow+\infty} \frac{x^3+4x}{x-x^3} \)
\( \displaystyle \lim_{x\rightarrow-\infty} \frac{x^4+x}{x-5x^2} \qquad \lim_{x\rightarrow-\infty} \frac{\sqrt{2}x^3+4x}{(x-4)^7} \)
📖 Corrigé ▼
Exercice 2 ⭐ ⭐ avec solution
Calculer les limites :
\( \displaystyle \lim_{x\rightarrow2} \frac{x^2+x-6}{x^3-8} \qquad \lim_{x\rightarrow1} \frac{x^3+x^2-2}{x^2+5x-6} \)
\( \displaystyle \lim_{x\rightarrow2} \frac{x^3-6x^2+11x-6}{x-2} \qquad \lim_{x\rightarrow2} \frac{\sqrt{x+7}-3}{x-2} \)
\( \displaystyle \lim_{x\rightarrow1} \frac{\sqrt{x^2+3x}-2}{x-1} \qquad \lim_{x\rightarrow0} \frac{\sqrt{x+1}-\sqrt{1-x}} {x-\sqrt{x}} \)
\( \displaystyle \lim_{x\rightarrow1} \frac{ \sqrt{x^2+x+2}-\sqrt{2x+2} }{ \sqrt{3x+1}-2 } \)
\( \displaystyle \lim_{x\rightarrow2} \frac{ \sqrt{2x}+\sqrt{4x+1}-5 }{x-2} \)
\( \displaystyle \lim_{x\rightarrow3} \frac{ \sqrt{x+1}-x^2+x+4 }{x-3} \)
\( \displaystyle \lim_{x\rightarrow1} \frac{x+\sqrt{x}-2}{x^2+x-2} \)
📖 Corrigé ▼
Exercice 3 ⭐ ⭐ avec solution
Calculer les limites :
\( \displaystyle \lim_{x\rightarrow2^+} \frac{x+7}{x-2} \qquad \lim_{x\rightarrow1^+} \frac{x^2+5}{1-x} \)
\( \displaystyle \lim_{x\rightarrow2^+} \frac{x+7}{x^2-4} \qquad \lim_{x\rightarrow3^+} \frac{x+4}{x^2+x-12} \)
\( \displaystyle \lim_{x\rightarrow0^+} \left( \frac{1}{x} - \frac{3+x}{x^3} \right) \)
\( \displaystyle \lim_{x\rightarrow4^+} \frac{ \sqrt{x+12}-\sqrt{3x-4} }{ x^2-8x+16 } \)
\( \displaystyle \lim_{x\rightarrow1} \frac{x^2+|x-1|-1}{x^2-x} \)
📖 Corrigé ▼
Exercice 4 ⭐ ⭐ avec solution
Calculer les limites :
\( \displaystyle \lim_{x\rightarrow+\infty} \left( \sqrt{x^2+4x-5}+x \right) \)
\( \displaystyle \lim_{x\rightarrow-\infty} \left( \sqrt{x^2-4x+7}-3x \right) \)
\( \displaystyle \lim_{x\rightarrow-\infty} \left( \sqrt{x^2+x-3}-3x \right) \)
\( \displaystyle \lim_{x\rightarrow-\infty} \left( \sqrt{x^2+5}+4x \right) \)
\( \displaystyle \lim_{x\rightarrow+\infty} \left( \sqrt{x^2-1}-x \right) \qquad \lim_{x\rightarrow-\infty} \left( \sqrt{x^2+4x-3}+2x \right) \)
\( \displaystyle \lim_{x\rightarrow+\infty} \left( \frac{x}{3}+2+ \sqrt{\frac{x^2}{9}-2x+3} \right) \)
\( \displaystyle \lim_{x\rightarrow+\infty} \left( \sqrt{9x^2+x} - \sqrt{4x^2+3} - \sqrt{x^2+4} \right) \)
\( \displaystyle \lim_{x\rightarrow+\infty} \frac{\sqrt{x^2+1}+x}{x+2} \qquad \lim_{x\rightarrow+\infty} \frac{\sqrt{x}-1}{x+1} \)
\( \displaystyle \lim_{x\rightarrow-\infty} \frac{x-2}{\sqrt{9x^2+x}} \qquad \lim_{x\rightarrow+\infty} \frac{\sqrt{x^2-4}}{1-\sqrt{x}} \)
\( \displaystyle \lim_{x\rightarrow+\infty} \frac{\sqrt{x}} {\sqrt{x+\sqrt{x+\sqrt{x}}}} \)
\( \displaystyle \lim_{x\rightarrow+\infty} \frac{x}{\sqrt{x}-1} \)
📖 Corrigé ▼
Exercice 5 ⭐ ⭐ avec solution
Calculer les limites :
\( \displaystyle \lim_{x\rightarrow0} \frac{\sin(2x)}{3x} \qquad \lim_{x\rightarrow0} \frac{\tan(4x)}{5x} \)
\( \displaystyle \lim_{x\rightarrow0} \frac{\sin(2x)}{\tan(3x)} \qquad \lim_{x\rightarrow0} \frac{x+\sin x}{x-\tan x} \)
\( \displaystyle \lim_{x\rightarrow0} \frac{1-\cos x}{x\tan(2x)} \qquad \lim_{x\rightarrow0} \frac{\sin x-\cos x+1}{x} \)
\( \displaystyle \lim_{x\rightarrow+\infty} x^2 \left( 1-\cos\left(\frac{1}{x}\right) \right) \qquad \lim_{x\rightarrow1} \frac{x^2-1}{\sin(1-x)} \)
\( \displaystyle \lim_{x\rightarrow\frac{\pi}{4}} \frac{\sqrt{2}\cos x-1} {x-\frac{\pi}{4}} \)
\( \displaystyle \lim_{x\rightarrow\pi} \frac{\cos x-1}{x-\pi} \qquad \lim_{x\rightarrow0} \frac{\cos x-3}{x^2+1} \)
📖 Corrigé ▼